In: Statistics and Probability
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 72 inches and standard deviation 4 inches.
(a) What is the probability that an 18-year-old man selected at
random is between 71 and 73 inches tall? (Round your answer to four
decimal places.)
(b) If a random sample of twelve 18-year-old men is selected, what
is the probability that the mean height x is between 71
and 73 inches? (Round your answer to four decimal places.)
(c) Compare your answers to parts (a) and (b). Is the probability
in part (b) much higher? Why would you expect this?
The probability in part (b) is much higher because the standard deviation is larger for the x distribution.
The probability in part (b) is much lower because the standard deviation is smaller for the x distribution.
The probability in part (b) is much higher because the standard deviation is smaller for the x distribution.
The probability in part (b) is much higher because the mean is larger for the x distribution
The probability in part (b) is much higher because the mean is smaller for the x distribution.
a)
Here, μ = 72, σ = 4, x1 = 71 and x2 = 73. We need to compute P(71<= X <= 73). The corresponding z-value is calculated using Central Limit Theorem
z = (x - μ)/σ
z1 = (71 - 72)/4 = -0.25
z2 = (73 - 72)/4 = 0.25
Therefore, we get
P(71 <= X <= 73) = P((73 - 72)/4) <= z <= (73 -
72)/4)
= P(-0.25 <= z <= 0.25) = P(z <= 0.25) - P(z <=
-0.25)
= 0.5987 - 0.4013
= 0.1974
b)
Here, μ = 72, σ = 1.1547, x1 = 71 and x2 = 73. We need to compute P(71<= X <= 73). The corresponding z-value is calculated using Central Limit Theorem
z = (x - μ)/σ
z1 = (71 - 72)/1.1547 = -0.87
z2 = (73 - 72)/1.1547 = 0.87
Therefore, we get
P(71 <= X <= 73) = P((73 - 72)/1.1547) <= z <= (73 -
72)/1.1547)
= P(-0.87 <= z <= 0.87) = P(z <= 0.87) - P(z <=
-0.87)
= 0.8078 - 0.1922
= 0.6156
c)
The probability in part (b) is much higher because the standard deviation is smaller for the x distribution.