In: Economics
What is the payback period for a project with the following characteristics, given a minimum attractive rate of return (MARR) of 12%?
First Cost $20,000
Annual Benefits $8,000
Annual Maintenance $2,000 in year 1, then increases by $500 per year
Salvage value $2,000
Useful Life 10 years
First Cost = $20,000
Annual Benefits = $8,000
Annual Maintenance = $2,000 in year 1 and then it increases by $500 per year
Salvage value = $2,000
Life = 10 years
Calculate the Pay-back Period.
Step 1 – Calculate the Annual Net Cash Flow
Annual Net Cash Flow = Annual Benefits – Annual Maintenance Costs
| 
 Year  | 
 Annual Benefits  | 
 Annual Maintenance  | 
 Net Benefits  | 
| 
 1  | 
 8000  | 
 2000  | 
 6000  | 
| 
 2  | 
 8000  | 
 2500  | 
 5500  | 
| 
 3  | 
 8000  | 
 3000  | 
 5000  | 
| 
 4  | 
 8000  | 
 3500  | 
 4500  | 
| 
 5  | 
 8000  | 
 4000  | 
 4000  | 
| 
 6  | 
 8000  | 
 4500  | 
 3500  | 
| 
 7  | 
 8000  | 
 5000  | 
 3000  | 
| 
 8  | 
 8000  | 
 5500  | 
 2500  | 
| 
 9  | 
 8000  | 
 6000  | 
 2000  | 
| 
 10  | 
 8000  | 
 6500  | 
 1500  | 
Step 2 – Calculate the discounted Pay-back Period at MARR of 12%
| 
 Year  | 
 CF  | 
 PV Factor  | 
 DCF  | 
 CCF  | 
| 
 0  | 
 $-20,000  | 
 1  | 
 $-20,000  | 
 $-20,000  | 
| 
 1  | 
 $6,000  | 
 0.89  | 
 $5,357.14  | 
 $-14,642.86  | 
| 
 2  | 
 $5,500  | 
 0.8  | 
 $4,384.57  | 
 $-10,258.29  | 
| 
 3  | 
 $5,000  | 
 0.71  | 
 $3,558.9  | 
 $-6,699.39  | 
| 
 4  | 
 $4,500  | 
 0.64  | 
 $2,859.83  | 
 $-3,839.56  | 
| 
 5  | 
 $4,000  | 
 0.57  | 
 $2,269.71  | 
 $-1,569.85  | 
| 
 6  | 
 $3,500  | 
 0.51  | 
 $1,773.21  | 
 $203.36  | 
In between 5th and 6th year the initial cost is recovered. Using interpolation
Pay-Back Period = 5 + [$-1,569.85 – 0 ÷ $-1,569.85 – ($203.36)] * 1
Pay-Back Period = 5.89 years
The discounted pay-back period will be 5.89 years.
Note – The simple or conventional payback period will be
| 
 Year  | 
 CF  | 
 NCF  | 
| 
 0  | 
 $-20,000  | 
 $-20,000  | 
| 
 1  | 
 $6,000  | 
 $-14,000  | 
| 
 2  | 
 $5,500  | 
 $-8,500  | 
| 
 3  | 
 $5,000  | 
 $-3,500  | 
| 
 4  | 
 $4,500  | 
 $1,000  | 
Pay-Back Period = 3 + (3,500 ÷ 4,500) = 3.78 years.