Question

In: Statistics and Probability

Chapter 2 Exercise is divided in to 2 sections A and B. Data for this assignment...

Chapter 2 Exercise is divided in to 2 sections A and B. Data for this assignment is under Data files in module Ex2-30-e8.xls (for A) and Ex2-34-e8.xls (for B). See data under modules.

A) The following data give the weekly amounts spent on groceries for a sample of households.

$271

$363

$159

$ 76

$227

$337

$295

$319

$250

279

205

279

266

199

177

162

232

303

192

181

321

309

246

278

50

41

335

116

100

151

240

474

297

170

188

320

429

294

570

342

279

235

434

123

325

  1. Create a frequency table of 9 classes
  2. Use the classes as (x) to find the mean of the distribution
  3. Use the classes to find the variance and standard deviation -----------------------------------------  (B)The monthly issues of the Journal of Finance are available on the Internet. The table below shows the number of times an issue was downloaded over the last 33 months. Suppose you wish to summarize the number of downloads with a frequency distribution.(This data can be found under data in module titled-Ex2-34-e8.xls

312

2,753

2,595

6,057

7,624

6,624

6,362

6,575

7,760

7,085

7,272

5,967

5,256

6,160

6,238

6,709

7,193

5,631

6,490

6,682

7,829

7,091

6,871

6,230

7,253

5,507

5,676

6,974

6,915

4,999

5,689

6,143

7,086

  1. Find the mean, median, mode, minimum and maximum values as well as variance, standard deviation, range, Q1 and Q3.
  2. Use the data above to create a frequency distribution table with 11 classes and find the: mean and relative frequency .

Solutions

Expert Solution

Solution

Let x = amount ($) spent on groceries

Back-up Theory

Let xi =mid-point and fi be the frequency of ith classi. Then,

Mean (Average), µ, = Σ(i = 1, n)(xi.ri)/Σ(i = 1, n)(fi) ………………………….......................………. (1)

Variance, σ2 = Σ(i = 1, n){fi.(xi – µ)2}/ Σ(i = 1, n)(fi) or equivalently [{Σ(i = 1, n){fi.(xi)2} – µ2 ]...... . (2)

Standard deviation (SD), σ = sqrt(Variance) ……………………………………........................….. (3)

Now to work out the solution,

Final answers are given below. Back-up Theory and Details of calculations follow at the end.

Part (a)

Frequency Distribution

Maximum value: 570

Minimum value: 41

Range of values: 529

Stipulated number of classes: 9

Class width = 529/9 = 59 ~ 60

Class # i

Class Boundaries

Frequency

1

40 to 100

3

2

100 to 160

4

3

160 to 220

6

4

220 to 280

12

5

280 to 340

10

6

340 to 400

2

7

400 to 460

1

8

460 to 520

1

9

520 to 580

1

Total

40

Answer 1

Part (b)

Vide (1), mean = 254.5 Answer 2

[Details follow at the end after Part (c).]

Part (c)

Vide (2), variance = 10,509.7500 Answer 3

Vide (3), standard deviation = 102.52 Answer 4

[Details follow]

Class # i

Class Boundaries

Frequency fi

Mid-point xi

fi.xi

di =

xi - mean

di2

di2.fi

1

40 to 100

3

70

210

-184.5

34040.25

102120.75

2

100 to 160

4

130

520

-124.5

15500.25

62001

3

160 to 220

6

190

1140

-64.5

4160.25

24961.5

4

220 to 280

12

250

3000

-4.5

20.25

243

5

280 to 340

10

310

3100

55.5

3080.25

30802.5

6

340 to 400

2

370

740

115.5

13340.25

26680.5

7

400 to 460

1

430

430

175.5

30800.25

30800.25

8

460 to 520

1

490

490

235.5

55460.25

55460.25

9

520 to 580

1

550

550

295.5

87320.25

87320.25

Total

40

10180

243722.25

420390.00

Mean = 10180/40

254.5

Variance = 420390/40

10,509.7500

Standerd deviation = √6093.0563

102.52

DONE


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