In: Mechanical Engineering
a)
At 100 deg C, Air kinematic viscosity = 22.97*10-6 m2/s
Reynolds number Re = V*D /
= 70 * 0.05 / (22.97*10-6)
Re = 1.52*105
For commercial steel pipe, roughness = 0.046 mm
Relative roughness = 0.046 / D = 0.046 / 50 = 0.00092
From Moody diagram, for Re = 1.52*105 and relative roughness = 0.00092, we get friction factor f = 0.022
Velocity of sound at inlet a = (kRT)0.5 = (1.4 * 287 * (100 + 273))0.5 = 387.13 m/s
Inlet Mach number Ma = V / a = 70 / 387.13 = 0.181
From adiabatic flow in a duct tables, for k = 1.4 and Ma = 0.181 we get fL* / D = 18.5427
We get sonic length L* = 18.5427 * 0.05 / 0.022 = 42.14 m
Since the given length L = 60 m > 42.14 m, the inlet Ma will be reduced until the exit flow is sonic and mass flow will be reduced by frictional choking.
Hence, exit Ma = 1.0
b)
fL* / D = 0.022 * 60 / 0.05 = 26.4
For k = 1.4 and fL*/D = 26.4, we get from adiabatic duct flow tables that Ma = 0.155
Hence, the inlet Ma will be reduced to 0.155.
From adiabatic flow in a duct tables, for k = 1.4 and Ma = 0.155 we get T / T* = 1.194
Putting T = 100 deg C = 373 K, we get T* = 373 / 1.194 = 312.4 K = 39 deg C
The temperature varies from 100 deg C at inlet to 39 deg C at outlet. This will impact the constant kinematic viscosity assumption. Hence, Re and therefore, f will vary considerably.