Question

In: Math

sin(tan-1 x), where |x| < 1, is equal to: (a) x/√(1 – x2) (b) 1/√(1 – x2) (c) 1/√(1 + x2) (d) x/√(1 + x2)

sin(tan-1 x), where |x| < 1, is equal to:

(a) x/√(1 – x²)

(b) 1/√(1 – x²)

(c) 1/√(1 + x²)

(d) x/√(1 + x²)

Solutions

Expert Solution

Correct Answer : (d) x / √(1 + x²)

Explanation :

Let tan-1 x = θ

Then, tan θ = x 

From this, we can write the sin θ and cos θ values as:

sin θ = x / √(1 + x²)

cos θ = 1 / √(1 + x²)

Now, consider the given question, 

sin (tan-1 x) = sin θ

                      = x / √(1 + x²)  Since |x| < 1

Therefore, sin(tan-1 x) = x/√(1 + x2).


(d) x/√(1 + x²)

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