Question

Assume that the firework has a mass of m_0 = 0.30~\text{kg}m​0​​=0.30 kg and is launched from a cannon at an angle of \theta_0 = 41.8^\circθ​0​​=41.8​∘​​ with an initial velocity of | v_0 | = 20~\text{m/s}∣v​0​​∣=20 m/s. Just as the firework reaches its hight point in its trajectory, it explodes into two pieces. Immediately after the explosion, the first piece, with a mass of m_1 = 0.2~\text{kg}m​1​​=0.2 kg flies off at an angle \theta_1 = 150^\circθ​1​​=150​∘​​ relative to the positive (forward) horizontal axis at a velocity of | v_1 | = 5~\text{m/s}∣v​1​​∣=5 m/s relative to the ground. Calculate the trajectory angle, \theta_2θ​2​​ of the second piece immediately after the explosion. Assume the second piece has a mass of m_2 = 0.1~\text{kg}m​2​​=0.1 kg, neglect the effect of air resistance, and report your result as an angle relative to the positive (forward) horizontal axis.

Answer 1