In: Statistics and Probability
A quality analyst wants to construct a sample mean chart for controlling a packaging process. Each day last week, he randomly selected six packages and weighed each. The data from that activity appears below.
| 
 Weight (in grams)  | 
||||||
| 
 Day  | 
 Package 1  | 
 Package 2  | 
 Package 3  | 
 Package 4  | 
 Package 5  | 
 Package 6  | 
| 
 Monday  | 
 23  | 
 22  | 
 23  | 
 24  | 
 23  | 
 21  | 
| 
 Tuesday  | 
 23  | 
 21  | 
 19  | 
 21  | 
 24  | 
 20  | 
| 
 Wednesday  | 
 20  | 
 19  | 
 20  | 
 21  | 
 19  | 
 20  | 
| 
 Thursday  | 
 18  | 
 19  | 
 20  | 
 19  | 
 21  | 
 22  | 
| 
 Friday  | 
 18  | 
 20  | 
 22  | 
 20  | 
 19  | 
 21  | 
To assist students, I am attaching the Factors for Determining Control Limits from your text
Sample size A2 D3 D4
2 1.880 0 3.268
3 1.023 0 2.574
4 0.729 0 2.282
5 0.577 0 2.115
6 0.483 0 2.004
7 0.419 0.076 1.924
8 0.373 0.136 1.864
9 0.337 0.184 1.816
10 0.308 0.223 1.777
12 0.266 0.284 1.716
Assuming three (3) sigma limits (corresponding to 99.73 percent), construct:
ANSWER::
Belwo is the screenshot of the formula applied -

Below is the screenshot of the result -

Since mean of sample 1 is out of control limit hence process is not in control.
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