In: Statistics and Probability
A quality analyst wants to construct a sample mean chart for controlling a packaging process. Each day last week, he randomly selected six packages and weighed each. The data from that activity appears below.
Weight (in grams) |
||||||
Day |
Package 1 |
Package 2 |
Package 3 |
Package 4 |
Package 5 |
Package 6 |
Monday |
23 |
22 |
23 |
24 |
23 |
21 |
Tuesday |
23 |
21 |
19 |
21 |
24 |
20 |
Wednesday |
20 |
19 |
20 |
21 |
19 |
20 |
Thursday |
18 |
19 |
20 |
19 |
21 |
22 |
Friday |
18 |
20 |
22 |
20 |
19 |
21 |
To assist students, I am attaching the Factors for Determining Control Limits from your text
Sample size A2 D3 D4
2 1.880 0 3.268
3 1.023 0 2.574
4 0.729 0 2.282
5 0.577 0 2.115
6 0.483 0 2.004
7 0.419 0.076 1.924
8 0.373 0.136 1.864
9 0.337 0.184 1.816
10 0.308 0.223 1.777
12 0.266 0.284 1.716
Assuming three (3) sigma limits (corresponding to 99.73 percent), construct:
ANSWER::
Belwo is the screenshot of the formula applied -
Below is the screenshot of the result -
Since mean of sample 1 is out of control limit hence process is not in control.
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