In: Physics
A 18.5 µF spherical capacitor is composed of two metallic spheres, one having a radius twice as large as the other. If the region between the spheres is a vacuum, determine the volume of this region.
capacitance of spherical capacitor , air filled
C =4πεo(ab / b-a )
Here a, b are radii of the spherical plates
Here given that b = 2a
therefore
C =4πεo ( 2a2/ a )
= 8πεoa
So a =
C / 8πεo
substitute given values
a = 18.5 x 10-6 F / 8 * 3.14 * 8.85 x 10
-12
= 8.32 x 103 m
Therefore
b =2a
= 1.66 x 10 4 m
............................................................................................................
Volume enclosed V enc = (4/3 ) πb3 - (4/3 )
πa3
= (4/3 ) π { (2a) 3 - a3 }
= (4/3 ) π(7a)3
Substitute 'a' value , we get
= (4/3 ) π(7*8.32 x 103)3
V enc = 1.68x
1013 m 3