1). A car is moving along a straight line defined to be the positive x direction....

1). A car is moving along a straight line defined to be the positive x direction. Its velocity is measured and found to be a function of time given by Vx(t)=(alpha)t^2 , where alpha is a known constant. The car was at the point x = A at the time t = 2sec. Find the car's position as a function of time. How fast would the car be going just before it hits a wall located at x = L? (Give Law or Definition. Give Application. Give Result.) (The professors answer is v(t*)= (alpha)((3(L+8alpha/3-A))/alpha)^2/3) Please give as much explanation as possible!

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genius_generous answered 1 year ago

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