In: Physics
23) In a 5000 m race, the athletes run 1212 laps; each lap is 400 m. Kara runs the race at a constant pace and finishes in 17.9 min. Hannah runs the race in a blistering 15.3 min, so fast that she actually passes Kara during the race.
How many laps has Hannah run when she passes Kara?
D = distance traveled to complete the race = 5000 m
tk = time taken by kara to complete the race = 17.9 min = 17.9 x 60 = 1074 sec
Speed of kara is given as
vk = D/tk Eq-1
th = time taken by hannah to complete the race = 15.3 min = 15.3 x 60 = 918 sec
Speed of hannah is given as
vh = D/th Eq-2
Using Eq-1 and Eq-2, relative speed is given as
v = vh - vk = (D/th ) - (D/tk)
t = time
Using the equation for one lap as
v t = 400
((D/th ) - (D/tk)) t = 400
((5000/918) - (5000/1074)) t = 400
t = 505.61 sec
distance traveled by hannah is given as
d = vh t
d = (5000/918) (505.61)
d = 2753.87 m
number of laps are given as
n = d/400
n = 2753.87/400
n = 6.88