In: Statistics and Probability
In testing H0: μ1 - μ2 = 0 versus Ha: μ1 - μ2 ≠ 0, the computed value of the test statistic is z = 1.98. The P-value for this two-tailed test is then:
a. .0478
b. .2381
c. .4761
d. .0239
e. .2619
Solutoion:
H0: μ1 - μ2 = 0 versus Ha: μ1 - μ2 ≠ 0
z = 1.98
Using Normal Table,
The P-value for this two-tailed test = 2*P(z > 1.98) = 2*(1-P(z<1.98)) = 2*(1-0.97615)) = 2*(1-0.9762)) = 0.0478
a. .0478