In testing H0: μ1 - μ2 = 0 versus Ha: μ1 - μ2 ≠ 0, the...

In testing H₀: μ₁ - μ₂ = 0 versus H_a: μ₁ - μ₂ ≠ 0, the computed value of the test statistic is z = 1.98. The P-value for this two-tailed test is then:

a. .0478

b. .2381

c. .4761

d. .0239

e. .2619

Solutions

Expert Solution

Solutoion:

H0: μ1 - μ2 = 0 versus Ha: μ1 - μ2 ≠ 0

z = 1.98

Using Normal Table,

The P-value for this two-tailed test = 2*P(z > 1.98) = 2*(1-P(z<1.98)) = 2*(1-0.97615)) = 2*(1-0.9762)) = 0.0478

a. .0478

orchestra answered 1 year ago

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