In: Physics
A solid cylinder initially rolling with a translational speed of 4.5m/s rolls down a vertical drop of 0.625m. The cylinder has a mas of 7.25 Kg and a diameter of 0.115m. Ignore frictional losses and assume the mass of the cylinder is distributed uniformly. find transnational speed at the bottom of the drop
The initial total energy at the height h is
And for a solid cylinder, the moment of inertia is
And for rolling without sliping, we have
And so, we have
The total final energy at the bottom ( similar to the preivious
result with h = 0 in this case ) is
And the conservation of energy implies
So, given h = 0.625 m, and g = 9.8 m/s^2 and
And so, the translational speed at the bottom is