In: Statistics and Probability
A study of randomized controlled trial of animals facilitated therapy with dolphins in the treatment of (mild and moderate) depression collected the data as follows:
| Depression Improved | |||
|---|---|---|---|
| Treatment | Yes | No | Total | 
| Dolphin | 10 | 5 | 15 | 
| Control | 3 | 12 | 15 | 
| Total | 13 | 17 | 30 | 
Is the distribution of patients' depression significantly different between dolphin treatment and control treatment? Is there a treatment effect or could such a difference be explained by chance? Use the 8 step procedure to answer this question.
Solution:
Here, we have to use chi square test for independence of two categorical variables.
Null hypothesis: H0: The distribution of patients' depression is significantly different between dolphin treatment and control treatment.
Alternative hypothesis: Ha: The distribution of patients' depression is significantly different between dolphin treatment and control treatment.
We assume/given level of significance = α = 0.05
Test statistic formula is given as below:
Chi square = ∑[(O – E)^2/E]
Where, O is observed frequencies and E is expected frequencies.
E = row total * column total / Grand total
We are given
Number of rows = r = 2
Number of columns = c = 2
Degrees of freedom = df = (r – 1)*(c – 1) = 1*1 = 1
α = 0.05
Critical value = 3.841459
(by using Chi square table or excel)
Calculation tables for test statistic are given as below:
| 
 Observed Frequencies  | 
|||
| 
 Depression Improved  | 
|||
| 
 Treatment  | 
 Yes  | 
 No  | 
 Total  | 
| 
 Dolphin  | 
 10  | 
 5  | 
 15  | 
| 
 Control  | 
 3  | 
 12  | 
 15  | 
| 
 Total  | 
 13  | 
 17  | 
 30  | 
| 
 Expected Frequencies  | 
|||
| 
 Depression Improved  | 
|||
| 
 Treatment  | 
 Yes  | 
 No  | 
 Total  | 
| 
 Dolphin  | 
 6.5  | 
 8.5  | 
 15  | 
| 
 Control  | 
 6.5  | 
 8.5  | 
 15  | 
| 
 Total  | 
 13  | 
 17  | 
 30  | 
| 
 Calculations  | 
|
| 
 (O - E)  | 
|
| 
 3.5  | 
 -3.5  | 
| 
 -3.5  | 
 3.5  | 
| 
 (fo-fe)^2/fe  | 
|
| 
 1.884615  | 
 1.441176  | 
| 
 1.884615  | 
 1.441176  | 
Test Statistic = Chi square = ∑[(O – E)^2/E] = 6.651584
χ2 statistic = 6.651584
P-value = 0.009907
(By using Chi square table or excel)
P-value < α = 0.05
So, we reject the null hypothesis
There is not sufficient evidence to conclude that the distribution of patients' depression is significantly different between dolphin treatment and control treatment.