There have a thin and symmetry wing. aspect ratio is 10, span is 5m, taper ratio...

There have a thin and symmetry wing. aspect ratio is 10, span is 5m, taper ratio is 0.8 and δ＝τ＝0.055. wing's speed is 180km/h and lift is 1.000N. Determine this wing's angle of attack(air density is 1.23Kg/m³)

Expert Solution

GIVEN :

Aspect ratio, AR = 10

Span, S = 5m

Taper ratio = 0.8

= 0.055

Wing's Speed, V = 180 km/hr

Lift, L = 1000N

SOLN :

Drag Coefficient = C_L = / [1 + ( / .AR)] = 0.055 / [1 + (0.055 / .10)] = 0.0549

Angle of attack, = { [ 2.L / (.V²) ] - }x (1 / C_L) = { [2x1000 / (1.23 x 50²) ] - 0.055 } x (1/0.0549) = 10.825 deg.

samet mamat answered 2 years ago

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