Question

In: Computer Science

An ISP is granted the block 80.70.56.0/21. The ISP needs to allocate addresses for two organizations...

An ISP is granted the block 80.70.56.0/21. The ISP needs to allocate addresses for

two organizations each with 408 hosts, two organizations each with 128 hosts, and three

organizations each with 42 hosts.

• Find the number and range of addresses in the ISP block.

• Find the range of addresses for each organization and the range of unallocated addresses.

• Show the outline of the address distribution and the forwarding table.

Solutions

Expert Solution

Given Major Network address of the block is : 80.70.56.0/21

Network ID = 21 bits.

Host ID = 32 - 21 = 11 bits.

Number of addresses possible = 211 = 2048.

Range:

Network:: 01010000.01000110.00111 000.00000000 ==> 80.70.56.0/21
Broadcast: 01010000.01000110.00111 111.11111111 ==>80.70.63.255
HostMin: 80.70.56.1   
HostMax: 80.70.63.254

Therefore, Address Range is 80.70.56.0 - 80.70.63.255

Address distribution and Unallocated address range:

Subnet/ Organization Number of Hosts Addresses required Number of Hosts Addresses allocated Network Address Subnet Mask Host Address Range Broadcast Address Number of addresses unallocated Address range unused
A 408 510 80.70.56.0 /23 80.70.56.1-80.70.57.254 80.70.57.255 102 80.70.57.153-80.71.57.254
B 408 510 80.70.58.0 /23 80.70.58.1-80.70.59.254 80.70.59.255 102 80.70.59.153-80.70.59.254
C 128 254 80.70.60.0 /25 80.70.60.1-80.70.60.254 80.70.60.255 126 80.70.60.129-80.70.60.254
D 128 254 80.70.61.0 /25 80.70.61.1-80.70.61.254 80.70.61.255 126 80.70.61.129-80.70.61.254
E 42 62 80.70.62.0 /26 80.70.62.1-80.70.62.62 80.70.62.63 20 80.70.62.43-80.70.62.62
F 42 62 80.70.62.64 /26 80.70.62.65-80.70.62.126 80.70.62.127 20 80.70.62.107-80.70.62.126
G 42 62 80.70.62.128 /26 80.70.62.129-80.70.62.191 80.70.62.192 20 80.70.62.172-80.70.62.191

   Address Range unallocated is : 80.70.62.193 - 80.70.63.255

Forwarding Table:

Organization Network ID Subnet mask Interface
A 80.70.56.0 255.255.254.0 (/23) e0
B 80.70.58.0 255.255.254.0 (/23) e1
C 80.70.60.0 255.255.255.128 (/25) e2
D 80.70.61.0 255.255.255.128 (/25) e3
E 80.70.62.0 255.255.255.192 (/26) e4
F 80.70.62.64 255.255.255.192 (/25) e5
G 80.70.62.128 255.255.255.192 (/25) e6
- 0.0.0.0 0.0.0.0 e7 (default entry)

Related Solutions

An ISP is granted a block 10.48.0.0/16. The ISP wants to allocate addresses as follows: Group...
An ISP is granted a block 10.48.0.0/16. The ISP wants to allocate addresses as follows: Group 1: 16 customers, each with 64 addresses Group 2: 64customers, each with 16 addresses Group 3: 16customers, each with 32 addresses. a.Find the subnet mask, first and last addresses of 4th customer of each group. b.Find the number of addresses available with the ISP for future customers
A block of addresses is granted to a small organization. one of the addresses is 172.10.0.84/20....
A block of addresses is granted to a small organization. one of the addresses is 172.10.0.84/20. a) What are the first and the last addresses of this block? b) Determine the number of addresses granted to this small organization. c) The network administrator of this small organization wants to create eight subnets. Determine i) the subnet mask, ii) the address of each subnet, iii) number of addresses in each subnet, vi) the range of IP addresses in each subnet, and...
ISP have been allocated the address block 200.23.16.0/20 ISP, wants to divide its address block into...
ISP have been allocated the address block 200.23.16.0/20 ISP, wants to divide its address block into four equal sized address blocks and give one to each of four organizations. Write the address range and also subnet mask for each organization
Find the number of addresses in a block of classless addresses if one of the addresses...
Find the number of addresses in a block of classless addresses if one of the addresses is 101.10.2.8/29. Total addresses= Usable addresses= briefly explain your answer
A network administrator has a block of IP addresses: 10.5.4.0/23. From this block of IP addresses,...
A network administrator has a block of IP addresses: 10.5.4.0/23. From this block of IP addresses, he created 32 subnets of the same size with a prefix of /28. He wants to determine the directed broadcast address for each subnet. He wrote down a list of possible broadcast addresses. Select the IP addresses that do not correspond to a broadcast address for any subnets he created. Choose two options. a) 10.5.5.207 b) 10.5.5.159 c) 10.5.5.7 d) 10.5.4.78 e) 10.5.4.47 f)...
1) Suppose we have the following IP addresses for two different organizations, we have to create...
1) Suppose we have the following IP addresses for two different organizations, we have to create 5 networks having 30 hosts in it. Find first sub network ID, Fist address, Last address and Broadcast for each of the following given addresses? a) 14.23.120.8 b) 252.5.15.111
4) An organization where you are assigned as a network admin is granted a block of...
4) An organization where you are assigned as a network admin is granted a block of addresses with the beginning address 14.24.74.0/24. The organization needs to have 3 subblocks of addresses to use in its three subnets as shown below. Create address subblocks for these 3 subnets based on the given address block. ❑ subnet 1: One subblock of 120 addresses. ❑ subnet 2: One subblock of 60 addresses. ❑ subnet 3: One subblock of 10 addresses
Find the network address, the direct broadcast address, and the number of addresses in a block;...
Find the network address, the direct broadcast address, and the number of addresses in a block; if one of the addresses in this block is 175.120.240.17/19
Classless Subnetting 200.30.0.0/16 Group Blocks Needed Addresses Per Block Host Bits CIDR Total Addresses Increment #...
Classless Subnetting 200.30.0.0/16 Group Blocks Needed Addresses Per Block Host Bits CIDR Total Addresses Increment # Start Address End Address A 16 512 B 128 64 C 32 1024 D 512 4 E 256 16 Group C Block Start (Subnet ID) 1st Address Last Address End (Broadcast) 1 2 3 4 5
Problem 1. Network Address Suppose an ISP has the following IP address block: 130.12.128.0/23 a. Assume...
Problem 1. Network Address Suppose an ISP has the following IP address block: 130.12.128.0/23 a. Assume that the ISP wants to divide its address block (130.12.128.0/23) into two equal-sized contiguous address blocks, and give one of these address blocks to its customers (C1 and C2). Provide network addresses (of the form a.b.c.d/x) for C1 and C2. b. Now let’s assume that the ISP wants to divide its address block (130.12.128.0/23) into four equal-sized contiguous address blocks, and give one of...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT