Question

Classless Subnetting

200.30.0.0/16

Group	Blocks Needed	Addresses Per Block	Host Bits	CIDR	Total Addresses	Increment #	Start Address	End Address
A	16	512
B	128	64
C	32	1024
D	512	4
E	256	16

Group C

Block	Start (Subnet ID)	1st Address	Last Address	End (Broadcast)
1
2
3
4
5

Answer 1

Look at the first address 200.30.0.0/16 means we have total 65535 addresses as subnet mask of class B is 255.255.0.0 where total number of 0s are 16 in binary which gives 2^16=65535 addresses which we will divide as per the demand given in the block and addresses per block.

Group A need 16 blocks and each block contain 512 hosts so total usable 16x512=8,192‬ addresses and 1 subnet gives 256 address so 8912/256=32 subnet starting from 200.30.0.0 to 200.30.31.255 gives 8192 addresses.

Group	Blocks Needed	Addresses Per Block	Host Bits	CIDR	Total Addresses	Increment #	Start Address	End Address
A	16	512	9	/23	8190	7 bit [16+7]=23 bit	200.30.0.0	200.30.31.255
B	128	64	6	/26	8190	10[16+10]=26 bit	200.30.32.0	200.30.63.255
C	32	1024	10	/22	32766	6=[16+6] =22bit	200.30.64.0	200.30.191.255
D	512	4	3	/29	4094	13=[16+13]29 bit	200.30.192.0	200.30.207.255
E	256	16	4	/28	4094	12=[16+12]= 28 bit	200.30.208.0	200.30.223.255

Block	Start (Subnet ID)	1st Address	Last Address	End (Broadcast)
1	200.30.0.0	200.30.0.1	200.30.31.254	200.30.31.255
2	200.30.32.0	200.30.32.1	200.30.63.254	200.30.63.255
3	200.30.64.0	200.30.64.1	200.30.191.254	200.30.191.255
4	200.30.192.0	200.30.192.1	200.30.207.254	200.30.207.255
5	200.30.208.0	200.30.208.1	200.30.223.254	200.30.223.255

Thanks