In: Statistics and Probability
Hoping to lure more shoppers downtown, a city builds a new public parking garage in the central business district. The city plans to pay for the structure through parking fees. For a random sample of 44 weekdays, daily fees collected averaged $126, with a standard deviation of $15.
What assumptions must you make in order to use these statistics for inference?
Find a 90% confidence interval for the mean daily income this parking garage will generate.
Explain in context what this confidence interval means.
Explain what 90% confidence means in this context.
Solution :
Given that,
Point estimate = sample mean = = 126
Population standard deviation =
= 15
Sample size = n =44
At 90% confidence level the z is
= 1 - 90% = 1 - 0.90 = 0.1
/ 2 = 0.1 / 2 = 0.05
Z/2 = Z0.05 = 1.645 ( Using z table )
Margin of error = E = Z/2
* (
/n)
= 1.645 * ( 15 / 44
)
= 3.7199
At 90% confidence interval estimate of the population mean
is,
- E <
<
+ E
126 - 3.7199 <
< 126 + 3.7199
122.2801 <
< 129.7199
( 122.2801 ,129.7199 )
At 90% confidence interval estimate of the population mean
is,( 122.2801 ,129.7199 )