An object moving with uniform acceleration has a velocity of 10.0 cm/s in the positive x-direction...

An object moving with uniform acceleration has a velocity of 10.0 cm/s in the positive x-direction when its x-coordinate is 2.73cm. If its x-coordinate 2.95 s later is −5.00 cm, what is its acceleration?

Expert Solution

As the object's final position is in negative x direction and accleration is uniform and initial velocity was in positive x direction, it means that accleration acts in negative x direction. The object will first move in posotve x direction and it will declerate to speed zero.And from there it will start to move in negative x direction with same accleration.

We will use the second equation of kinematics S=ut+1/2at²

S=net displacement, u=initial velocity, a =accleration.

S= -5-2.73 = -7.73

u=10

a = accleration in negative x direction

t=total time taken

-7.73 = 10t - 1/2at²

-7.73 = 10x2.95 - 0.5xax(2.95)²

a = 8.56 cm/s²

genius_generous answered 2 years ago

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