In: Physics
An object moving with uniform acceleration has a velocity of 10.0 cm/s in the positive x-direction when its x-coordinate is 2.73cm. If its x-coordinate 2.95 s later is −5.00 cm, what is its acceleration?
As the object's final position is in negative x direction and accleration is uniform and initial velocity was in positive x direction, it means that accleration acts in negative x direction. The object will first move in posotve x direction and it will declerate to speed zero.And from there it will start to move in negative x direction with same accleration.
We will use the second equation of kinematics S=ut+1/2at2
S=net displacement, u=initial velocity, a =accleration.
S= -5-2.73 = -7.73
u=10
a = accleration in negative x direction
t=total time taken
-7.73 = 10t - 1/2at2
-7.73 = 10x2.95 - 0.5xax(2.95)2
a = 8.56 cm/s2