Question

In: Statistics and Probability

Would Not Approve of Driving Drunk Would Not Care or Would Approve of Driving Drunk n1=40...

Would Not Approve of Driving Drunk Would Not Care or Would Approve of Driving Drunk
n1=40 n2=25
X¯1=2.1 X¯2=8.2
s1=1.8 s2=1.9

John Worrall and colleagues (2014) found that the fear of losing the good opinion of one’s family and peers kept people from driving home drunk. Let’s say we have two independent random samples of people: those who think that their peers would disapprove of them from driving drunk, and those who think that their peers would either not care or approve of their driving drunk. We ask each person in each group to self-report the number of times that he or she has driven drunk in the past 12 months. The results are in the table above.

Test the null hypothesis that the two population means are equal against the alternative hypothesis that the group whose peers would not approve of driving drunk has a lower mean rate of driving drunk. In your hypothesis test, assume that the unknown population standard deviations are unequal (σ1 ≠ σ2), and use an alpha level of .01.

1. Which of the following is the most appropriate statement of the null hypothesis for this test?

A. H0: μ1 > μ2

B. H1: μ1 ≠ μ2

C. H0: μ1 = 0

D. H0: μ1 = μ2

E. H1: μ1 < μ2

2.Which of the following is the most appropriate statement of the alternative or research hypothesis for this test? (Hint: Read the problem carefully.)

A. H0: μ1 > μ2

B. H1: μ1 ≠ μ2

C. H0: μ1 = 0

D. H0: μ1 = μ2

E. H1: μ1 < μ2

3. Is this a one-tailed or two-tailed test?

A. One-tailed

B. Two-tailed

4. Which of the following tests is the most appropriate for this problem?

A. Pooled variance t test

B. Separate variance t test

C. Dependent-samples t test

D. Difference between proportions z test

E. Chi-square test of independence

Solutions

Expert Solution

1) D. H0: μ1 = μ2

2) E. H1: μ1 < μ2

3) A. One-tailed

4) B. Separate variance t test

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