In: Statistics and Probability
A random sample of 25 CCRI students found that the average amount spent on textbooks for a course was $180 with a standard deviation of $30. Find a 95% 2-tailed confidence interval for the population mean (μ) of the amount a CCRI student spends on textbooks.
Solution :
Given that,
= 180
s =30
n = Degrees of freedom = df = n - 1 =25 - 1 = 14
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/
2= 0.05 / 2 = 0.025
t
/2,df = t0.025,24 = 2.064 ( using student t
table)
Margin of error = E = t/2,df
* (s /
n)
= 2.064 * (30 /
25)
= 12.38
The 95% confidence interval mean is,
- E <
<
+ E
180-12.38 <
< 180+ 12.38
167.62 <
< 192.38