In: Statistics and Probability
The prosecutor's examination of court records in a specific county shows that the mean sentence length for first-offense drug dealers is 23 months with a standard deviation of 2.5 months. The records show that the sentence lengths are normally distributed. (You will need to use the Z table or software for this question.)
1) What percentage of first-time convictions for drug dealing are 20 or fewer months in length? %
b) A defense attorney is concerned that his client's sentence was unusually harsh at 28 months. What percent of sentences are 28 months or longer? %
c) What is the sentence length that separates top (longest) 2.5% of the lengths from the rest? months
Solution :
Given that ,
a) P(x 20 )
= P[(x - ) / (20 - 23) / 2.5]
= P(z -1.20)
Using z table,
= 0.1151
percentage = 11.51%
b) P(x 28 ) = 1 - P(x 28)
= 1 - P[(x - ) / (28 - 23) / 2.5 ]
= 1 - P(z 2.0)
= 1 - 0.9772
= 0.0228
percent = 2.28%
c) Using standard normal table,
P(Z > z) = 2.5%
= 1 - P(Z < z) = 0.025
= P(Z < z) = 1 - 0.025
= P(Z < z ) = 0.975
= P(Z < 1.96 ) = 0.975
z = 1.96
Using z-score formula,
x = z * +
x = 1.96 * 2.5 + 23
x = 27.9 months
x = 28 months