In: Statistics and Probability
One particular morning, the length of time spent in the
examination rooms is recorded for each patient seen by each
physician at an orthopedic clinic.
Time in Examination Rooms (minutes) | |||
Physician 1 | Physician 2 | Physician 3 | Physician 4 |
33 | 31 | 19 | 27 |
23 | 32 | 29 | 31 |
27 | 33 | 30 | 31 |
30 | 32 | 26 | 27 |
25 | 43 | 29 | 32 |
35 | 32 | 26 | 31 |
20 | 24 | 41 | |
31 |
Fill in the missing data. (Round your p-value
to 4 decimal places, mean values to 1 decimal place, and other
answers to 2 decimal places.)
Treatment | Mean | n | Std. Dev |
Physician 1 | |||
Physician 2 | |||
Physician 3 | |||
Physician 4 | |||
Total | |||
One-Factor ANOVA | |||||
Source | SS | df | MS | F | p-value |
Treatment | |||||
Error | |||||
Total | |||||
(a) Based on the given hypotheses, choose the correct
option.
H0: μ1 = μ2
= μ3 = μ4
H1: Not all the means are equal
α = 0.05
Reject the null hypothesis if F > 3.01
Reject the null hypothesis if F < 3.01
(b) Calculate the F for one factor.
(Round your answer to 2 decimal places.)
F for one factor is
(c) On the basis of the above findings, we reject the null
hypothesis. Is the statement true?
Yes
No
SUMMARY | |||||
Groups | Count, n | Sum | Mean | Std.Dev | |
Physician 1 | 7 | 193 | 27.6 | 5.41 | |
Physician 2 | 6 | 203 | 33.8 | 4.54 | |
Physician 3 | 8 | 214 | 26.8 | 3.92 | |
Physician 4 | 7 | 220 | 31.4 | 4.69 | |
Total | 28 | 830 | 119.58 | ||
ANOVA | |||||
Source of Variation | SS | df | MS | F | P-value |
Between Groups | 224.67 | 3 | 74.89 | 3.47 | 0.0318 |
Within Groups | 517.76 | 24 | 21.57 | ||
Total | 742.43 | 27 |
(a) Based on the given hypotheses, choose the
correct option.
H0: μ1 = μ2 = μ3 =
μ4
H1: Not all the means are equal
α = 0.05
Reject the null hypothesis if F > 3.01
(b) Calculate the F for one factor.
F for one factor = 3.47
(c) Yes, we reject the null
hypothesis.