In: Statistics and Probability
One particular morning, the length of time spent in the
examination rooms is recorded for each patient seen by each
physician at an orthopedic clinic.
| Time in Examination Rooms (minutes) | |||
| Physician 1 | Physician 2 | Physician 3 | Physician 4 | 
| 33 | 31 | 19 | 27 | 
| 23 | 32 | 29 | 31 | 
| 27 | 33 | 30 | 31 | 
| 30 | 32 | 26 | 27 | 
| 25 | 43 | 29 | 32 | 
| 35 | 32 | 26 | 31 | 
| 20 | 24 | 41 | |
| 31 | |||
Fill in the missing data. (Round your p-value
to 4 decimal places, mean values to 1 decimal place, and other
answers to 2 decimal places.)
| Treatment | Mean | n | Std. Dev | 
| Physician 1 | |||
| Physician 2 | |||
| Physician 3 | |||
| Physician 4 | |||
| Total | |||
| One-Factor ANOVA | |||||
| Source | SS | df | MS | F | p-value | 
| Treatment | |||||
| Error | |||||
| Total | |||||
(a) Based on the given hypotheses, choose the correct
option.
H0: μ1 = μ2
= μ3 = μ4
H1: Not all the means are equal
α = 0.05
Reject the null hypothesis if F > 3.01
Reject the null hypothesis if F < 3.01
(b) Calculate the F for one factor.
(Round your answer to 2 decimal places.)
F for one factor is      
       
(c) On the basis of the above findings, we reject the null
hypothesis. Is the statement true?
Yes
No
| SUMMARY | |||||
| Groups | Count, n | Sum | Mean | Std.Dev | |
| Physician 1 | 7 | 193 | 27.6 | 5.41 | |
| Physician 2 | 6 | 203 | 33.8 | 4.54 | |
| Physician 3 | 8 | 214 | 26.8 | 3.92 | |
| Physician 4 | 7 | 220 | 31.4 | 4.69 | |
| Total | 28 | 830 | 119.58 | ||
| ANOVA | |||||
| Source of Variation | SS | df | MS | F | P-value | 
| Between Groups | 224.67 | 3 | 74.89 | 3.47 | 0.0318 | 
| Within Groups | 517.76 | 24 | 21.57 | ||
| Total | 742.43 | 27 | |||
(a) Based on the given hypotheses, choose the
correct option.
H0: μ1 = μ2 = μ3 =
μ4
H1: Not all the means are equal
α = 0.05
Reject the null hypothesis if F > 3.01
(b) Calculate the F for one factor.
F for one factor = 3.47
(c) Yes, we reject the null
hypothesis.