In: Statistics and Probability
A garden seed wholesaler wishes to test the claim that tomato seeds germinate faster when each individual seed is "pelletized" within a coating of corn starch. The table below shows the germination times, in days, of six pelletized seeds. The table also shows the germination times in days of six un-coated seeds (the controls).
Pelletized: 8 6 7 8 10 7
Control: 11 8 9 10 7 11
Can you conclude that the mean germination time for pelletized seeds is less than the mean for the un-pelletized seeds? Use the α = 0.05 level of significance.
Ho : µ1 - µ2 = 0
Ha : µ1-µ2 < 0
Level of Significance , α =
0.05
Sample #1 ----> 1
mean of sample 1, x̅1= 7.67
standard deviation of sample 1, s1 =
1.366260102
size of sample 1, n1= 6
Sample #2 ----> 2
mean of sample 2, x̅2= 9.333
standard deviation of sample 2, s2 =
1.63
size of sample 2, n2= 6
difference in sample means = x̅1-x̅2 =
7.667 - 9.3333 =
-1.6667
std error , SE = √(s1²/n1+s2²/n2) =
0.8692
t-statistic = ((x̅1-x̅2)-µd)/SE = ( -1.6667
/ 0.8692 ) = -1.9174
Degree of freedom, = 9
t-critical value , t* =
-1.8331 (excel function: =t.inv(α,df)
Decision: | t-stat | > | critical value |, so,
Reject Ho
p-value = 0.04371 [
excel function: =T.DIST(t stat,df) ]
Conclusion: p-value<α , Reject null
hypothesis
yes, you conclude that the mean germination time for pelletized seeds is less than the mean for the un-pelletized seeds