A mixture contains 2.3 mol of cyclohexane (C6H12) and 3.8 mol of 2-methylpentane (C6H14). At 35°C,...

A mixture contains 2.3 mol of cyclohexane (C₆H₁₂) and 3.8 mol of 2-methylpentane (C₆H₁₄). At 35°C, the vapor pressure of cyclohexane is 150 torr and that of 2-methylpentane is 313 torr. Assume this is an ideal solution. What is the vapor pressure of cyclohexane above the solution?

Expert Solution

moles of cyclohexane = 2.3 moles

moles of 2-methylpentane = 3.8 moles

mole fraction of cyclohexane = moles of cyclohexane/(moles of cyclohexane + 2-methylpentane)

= 2.3/(2.3+3.8)

= 0.377
Pi = P°i* Xi
P(C6H12) = (150 torr) (0.377) = 56.55 torr.

queen_honey_blossom answered 2 years ago

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