In: Chemistry
Mandalorian iron, also known by its Mando'a name of beskar, was an extremely durable iron ore whose only known source was the Outer Rim world of Mandalore and its moon, Concordia.
The battle at The Sarlacc Pit in The Return of the Jedi offers us a rare opportunity to study the composition of the rare and coveted mandalorian armor worn by Boba Fett. In this battle Boba Fett fell into the gaping maw of The Sarlacc, where he would be slowly digested over the course a thousand years. If the molarity of the HCl in The Sarlacc stomach is 0.15M, upon which, over the course of a thousand years, four tons (4000 Liters) is produced, we can then titrate the stomach acid after a thousand years and treat the iron content of the mandalorian armor as an antacid tablet containing a diprotic base, since:
Fe + 2 HCl(aq) -> Fe2+(aq) + 2 Cl-(aq) + H2(g)
If after 1000 years, it took 21.85 mL of 0.1337 M NaOH to neutralize a 25.00 mL sample of The Sarlacc’s stomach acid, what was the mass % of Iron in Boba Fett’s mandalorian armor.
The last known Imperial medical record reports Boba Fett’s mass as 78.12 kg. The last known sensor scan from Boba Fett’s ship, Slave I, reports 93.36 kg for Boba Fett with his armor on.
You may assume The Sarlaac eats only once a millenia since Jabba the Hutt’s death.
(Please assume that while Boba Fett escaped the Sarlacc Pit, his armor did not.)
is this a star warz based question, coz i am not a fan.
let's discuss the answer:
Molarity of HCl in Sarlaac stomach- 0.15M,
Volume of HCl produced - 4000 Liters
Mass of HCl present = (Molarity X volume) X Mol. wt. of HCl = 21900 g
Fe + 2 HCl(aq) -> Fe2+(aq) + 2 Cl-(aq) + H2(g)
it took 21.85 mL of 0.1337 M NaOH to neutralize a 25.00 mL sample of The Sarlacc’s stomach acid
present molarity of HCl - 0.1168
volume of HCl - 4000 L
Mass of HCl of left in the stomach - 17060.6 g
Mass of HCl used up to eat up the armor = 21900 g - 17060.6g = 4839.34 g = 4.89 kg
Boba Fett’s mass as--- 78.12 g
Boba Fett's mass with his armor on----93.36 kg
Mass of Armor - 15.24 kg
According to the Rxn
Fe + 2 HCl(aq) -> Fe2+(aq) + 2 Cl-(aq) + H2(g)
by stociometry
73 g HCl -----reacts with 56 g Fe
4.89 kg of HCl reacts with ----- (56/73) X 4.89 = 3.75 kg
hence, the armor of Boba contains 3.75 kg of Iron
Thank god for that, we saved him :P