A)An exactly 500 gram iron ore sample was determined to contain 242 grams of iron. What...

A)An exactly 500 gram iron ore sample was determined to contain 242 grams of iron. What is the mass percent of iron in the ore?

B) What are the coeffieceints for the following properly balaned reaction-

__Sodium phosphate reacts with___barium nitrate to from ___sodium nitrate and ____barium phosphate

C) What mass of iron is present in a 6.03 gram sample of iron (II) chloride?

Solutions

Expert Solution

A) mass percent of iron in the ore = mass of iron/ mass of iron ore x 100

= 242 grams / 500 grams x 100

= 48.4 %

B) 2 Na₃PO₄ + 3Ba(NO₃)₂ -------------> 6NaNO₃ + Ba₃(PO₄)₂

mass of iron is present in a 6.03 gram sample of iron (II) chloride

= [molar mass of Fe / molar mass of FeCl2] x mass of sample

= [55.8 g / 126.7 g ] x 6.03 grams

= 2.65 grams

queen_honey_blossom answered 1 year ago

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