Calculate the empirical formula for the titanium-iron ore with 31.63% oxygen, 31.56% titanium and 36.81% iron.

Expert Solution

mass of Oxygen = 31.63 g

moles of O = 31.63 / 16 = 1.977

mass of Ti = 31.56 g

moles of Ti = 31.56 / 47.66 = 0.662

mass of iron = 36.81 g

moles of Fe = 36.81 / 55.85 = 0.659

moles ratio :

O Ti Fe

1.977 0.662 0.659

3 1 1

Emperical formula = FeTiO3

queen_honey_blossom answered 1 year ago

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Question

Calculate the empirical formula for the titanium-iron ore with 31.63% oxygen, 31.56% titanium and 36.81% iron.

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