In: Chemistry
What is the pH of a solution made by mixing 25 mL of .050 M HNO3 into a final volume of 2.0 Liters of water?
Intial Final
M1 = 0.05M M2 =
V1 = 25ml V2 = 25+2000 =2025ml
M1V1 = M2V2
M2 = M1V1/V2 = 0.05*25/2025 = 0.000617M
HNO3 -------------> H^+ + NO3^-
0.000617M 0.000617M
[H^+] = [HNO3]
[H+] = 0.000617M
PH = -log[H+]
= -log0.000617 = 3.2097 >>>>>answer