In: Chemistry
What is the pH of a solution prepared by mixing 25 ml of 0.5 HCN with 75 ml of 0.20 NaCN. Ka = 6.2*10^-10 for HCN. Hint: remember to dilutions first.
HCN + NaCN is the buffer
25x0.5 75x0.20 mmoles
7.5/100 15/100 concentrations
the pH of this buffer is given by Hendersen equation as
pH = pKa + log [conjugate base] [acid]
= (10-log 6.2) + log 15x10-2/ 7.5x10-2
= 9.5086