Question

In: Chemistry

Wrapping double-helical DNA around histone octamers condenses the DNA by a factor of 7. Higher order...

Wrapping double-helical DNA around histone octamers condenses the DNA by a factor of 7. Higher order chromatin structures condense this DNA even further. During metaphase, the DNA is compacted by a factor of 1 × 104. How many centimeters would the naked double-helical DNA from a 50 Mb chromosome stretch? (Note: Assume the DNA remains in the B-form, which has a rise per base pair of 0.34 nm.)

A. 0.017cm

B. 0.17 cm

C. 0.68 cm

D. 1.7 cm

E. 6.8 cm

Solutions

Expert Solution

Correct option A: 0.017 cm

Length of fully extended (naked) 50 Mb chromosome stretch = 50 x106 bases x 0.34 nm

                                                                           = 17.0 x 106 nm                                     [1nm = 10-9 m]

          = 1.7 x 10-2 m = 0.017 cm                 [1 m = 100 cm]

Rise per base pair means the vertical distance (elevation) between two adjacent bases as they rise along the helix. It gives the length of the naked DNA itself.


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