Wrapping double-helical DNA around histone octamers condenses the DNA by a factor of 7. Higher order...

Wrapping double-helical DNA around histone octamers condenses the DNA by a factor of 7. Higher order chromatin structures condense this DNA even further. During metaphase, the DNA is compacted by a factor of 1 × 10⁴. How many centimeters would the naked double-helical DNA from a 50 Mb chromosome stretch? (Note: Assume the DNA remains in the B-form, which has a rise per base pair of 0.34 nm.)

A. 0.017cm

B. 0.17 cm

C. 0.68 cm

D. 1.7 cm

E. 6.8 cm

Solutions

Expert Solution

Correct option A: 0.017 cm

Length of fully extended (naked) 50 Mb chromosome stretch = 50 x10⁶ bases x 0.34 nm

= 17.0 x 10⁶ nm [1nm = 10^-9 m]

= 1.7 x 10^-2 m = 0.017 cm [1 m = 100 cm]

Rise per base pair means the vertical distance (elevation) between two adjacent bases as they rise along the helix. It gives the length of the naked DNA itself.

queen_honey_blossom answered 1 year ago

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