QUESTION 3 Use your TI83 (or Excel): A normally distributed population has a mean of 233...

QUESTION 3 Use your TI83 (or Excel): A normally distributed population has a mean of 233 and a standard deviation of 16. Determine the value of the 90th percentile. Round to the nearest whole number

Question 4 Use your TI83 (or Excel): A normally distributed population of adult American men heights has a mean of 58.5 inches and a standard deviation of 4.35 inches. Determine the height at the 1st percentile.

QUESTION 5 Use your TI83 (or Excel): A normally distributed population has a mean of 96 and a standard deviation of 5. Determine the value of the 25th percentile. Round to the nearest tenth

QUESTION 6: Use your TI83 (or Excel): A normally distributed population has a mean of 98.38 and a standard deviation of 0.5. Determine the value of the first quartile.

QUESTION 7 Use your TI83 (or Excel): A normally distributed population has a mean of 98.46 and a standard deviation of 0.32. Determine the value of the third quartile. Round to the nearest hundredth

QUESTION 8 Use your TI83 (or Excel): A normally distributed population has a mean of 90 and a standard deviation of 7. Determine the value of the first quartile. Round to the nearest tenth

Solutions

Expert Solution

3) mean = 233 , standard deviation =16, Percentile = 90th

value of the 90th percentile = 254

4) mean = 58.5 , standard deviation =4.35 Percentile = 1st

the height at the 1st percentile = 48.3803

5) mean = 96 , standard deviation =5 , Percentile = 25th

value of the 25th percentile =92.6

6)mean = 98.38 , standard deviation =0.5. Percentile = 25th

the value of the first quartile = 98.0428

7) mean = 98.46 , standard deviation =0.32, Percentile = 75th

the value of the third quartile = 98.68

8)mean = 90 , standard deviation =7, Percentile = 25th

he value of the first quartile = 85.3

orchestra answered 1 year ago

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