In: Chemistry
1/ A 10.64 mol sample of xenon
gas is maintained in a 0.8062 L container at
299.9 K. What is the pressure in atm calculated
using the van der Waals' equation for Xe gas under
these conditions? For Xe, a =
4.194 L2atm/mol2 and b =
5.105×10-2 L/mol.
(......) atm
2/ According to the ideal gas law, a 0.9174 mol sample of krypton gas in a 1.363 L container at 267.1 K should exert a pressure of 14.75atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For Kr gas, a = 2.318 L2atm/mol2 and b = 3.978×10-2 L/mol. (......) %
3/ According to the ideal gas law, a 9.560 mol sample of argon gas in a 0.8480 L container at 495.3 K should exert a pressure of 458.2 atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For Ar gas, a = 1.345 L2atm/mol2 and b = 3.219×10-2 L/mol. (......) %
1.
Van Der Waal's equation of state for a real gas is given by the following equation:
(P + a*(n/V)2)*((V/n)-b) = RT
We need to put the given values in the above equation, as shown below:
(P + 4.194*(10.64/0.8062)2)*((0.8062/10.64) - 0.05105) = 0.0821*299.9
This can be simplified to:
(P + 730.51)*0.0247 = 24.6218
So,
P = 266.324 atm
2.
Using the Van Der waal's equation of state in the same way as above, we calculate the pressure in this case as:
(P + 2.318*(0.9174/1.363)2)*((1.363/0.9174) - 0.03978) = 0.0821*261.7
Calculating in same way as above:
P = 13.809 atm
So the percent difference is calculated as:
((Ideal pressure - Van der Waal pressure)/Ideal pressure)*100
Putting values:
% difference = ((14.75-13.809)/14.75)*100 = 6.38%
3.
Using the Van Der waal's equation of state in the same way as above, we calculate the pressure in this case as:
(P + 1.345*(9.56/0.8480)2)*((0.8480/9.56) - 0.03219) = 0.0821*495.3
Calculating in same way as above:
P = 548.61 atm
So the percent difference is calculated as:
((|Ideal pressure - Van der Waal pressure|)/Ideal pressure)*100
% difference = ((|458.2-548.61|)/458.2)*100 = 19.73%