A flexible container at an initial volume of 6.13 L contains 9.51 mol of gas. More...

A flexible container at an initial volume of 6.13 L contains 9.51 mol of gas. More gas is then added to the container until it reaches a final volume of 16.3 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Expert Solution

Ans. Avogadro’s Law, equal volume of all gases have equal number of moles, at constant pressure and temperature.

That is, V1 / n1 = V2 / n2 P, T constant - equation 1

Putting the values for initial and final conditions-

6.13 L / 9.51 mol = 16.3 L / n2

Or, n2 = 16.3 L / (6.13 L / 9.51 mol)

Hence, n2 = 25.288 mol

Therefore, total (final) moles of gas after addition of new gases = 25.288 mol.

Now,

Moles of gas added later = Final no. of moles – Initial no. of moles

= 25.288 mol – 9.51 mol

= 15.78 mol

queen_honey_blossom answered 2 years ago

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