In: Statistics and Probability
The mean weight of a fire ant worker is 3.11 mg with a standard
deviation of .49 mg. Suppose we randomly select 14 different fire
ant workers having weights F1, F2, , F14. Let S = F1 + F2 + ...+F14
and let M = S/14. This means S is the sample sum and M is the
sample mean of the selected ant weights. (Note: random selection
means F1 F14 are independent.). Assume the Fis are normally
distributed.
a) What is the expected value of S?
b) What is the standard deviation of S?
c) What is the expected value of M?
d) What is the standard deviation of M?
e) What is the expected value of S-14*3.11?
f) What is the standard deviation of ZZ =
(S - 14*3.11)/(sqrt14*.49) |
Solution:-
Given that
The mean weight of a fire ant worker is 3.11 mg with a standard deviation of .49 mg. Suppose we randomly select 14 different fire ant workers having weights F1, F2, , F14. Let S = F1 + F2 + ...+F14 and let M = S/14. This means S is the sample sum and M is the sample mean of the selected ant weights.
a) What is the expected value of S?
E(S) = 14 * 3.11
= 43.54
b) What is the standard deviation of S?
=
= 1.8334
c) What is the expected value of M?
d) What is the standard deviation of M?
SD(M) =
= 0.1310
e) What is the expected value of S-14*3.11 ?
The expected value = 0
f) What is the standard deviation of ZZ = (S-14*3.11)/(sqrt14*.49)?
The standard deviation is 1.
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