A solution is made by combining 15.0 mL of 16.5 M acetic acid with 5.50 g...

A solution is made by combining 15.0 mL of 16.5 M acetic acid with 5.50 g of sodium acetate and diluting to a total volume of 1.50 L.

Calculate the pH of the solution.

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Expert Solution

no of moles of CH3COOH = molarity * volume in L

= 16.5*0.015 = 0.2475 moles

no of moles of CH3COONa = W/G.M.Wt = 5.5/82 = 0.067 moles

concentration of acetic acid = no of moles/volume in L = 0.2475/1.5 = 0.165M

concentration of sodium acetate = no of moles/volume in L = 0.067/1.5 = 0.0446M

PH = Pka + log[CH3COONa]/[CH3COOH]

= 4.75 + log0.0446/0.165

= 4.75-0.5681

= 4.1819 >>>>>answer

queen_honey_blossom answered 2 years ago

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