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In: Chemistry

What is [H3O+] and pH in a 0.10 M solution of HCN at 25

What is [H3O+] and pH in a 0.10 M solution of HCN at 25

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Expert Solution

We have , 0.10M HCN solution at 25oc & Ka for HCN = 4.0 * 10-10

                               HCN + H2O -----------> H3O+ + CN-

Intial concentration     0.1 M                         0 M       0 M

Change in concentration   -x                           +X         +X

Equilibrium concentration    (0.1-x)                   X             X

Ka = [H3O+][CN-] / [HCN]

4.0 * 10-10 = (X)(X) / (0.1-X)

4.0 * 10-10 = (X)(X) / (0.1)

        X2     = (0.1) * (4.0 * 10-10)

[H3O+] = X = 6.3 * 10-6 M

[H3O+] = 6.3 * 10-6 M

pH = -log[H3O+]

      = -log (6.3 * 10-6)

pH = 5.2


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