You are asked to prepare 1.4 L of a HCN/NaCN buffer that has a pH of...

You are asked to prepare 1.4 L of a HCN/NaCN buffer that has a pH of 9.78 and an osmotic pressure of 1.11 atm at 298 K.

What masses of HCN and NaCN should you use to prepare the buffer? (Assume complete dissociation of NaCN.)

Solutions

Expert Solution

Molarity = π/iRT = 1.11/(2*0.082*298)

= 0.0227 M

This is conc of CN- = 0.0227 M

We know that

pH = pKa + log (CN-/ HCN)

9.78 = 9.21 + log(0.0227-x/x)

0.0227-x / x = 3.715

x= 0.004814 moles

Mass of HCN = 0.004814*27 g/mol = 0.13 g

Mass of NaCN = (0.0227-0.004814)*49 = 0.876 g

queen_honey_blossom answered 1 year ago

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