Question

use the standard normal table to find the z-score that corresponds to the given percentile. if the area is not in the table, use the entry closest to the area. if the area is halfway between two entries, use the z-scores P65

Answer 1

We have to find

P₆₅

That means we have given left side area as 65 %

We convert the left side area in to decimal = 0.6500

We search for the area 0.6500 inside the body of the table

But the area 0.6500 is not present in the table

we can see 0.6500 area is between area 0.6480 and 0.6517

But 0.6517 is very closer to 0.6500 than 0.6480

So we select area 0.6517 to find the Z score for area 0.6500

Z score for area 0.6500 = Z score for area 0.6517 = Row headed number for 0.6517 + column headed number for 0.6517

Z score for area 0.6500 = Z score for area 0.6517 = 0.3 + 0.09

Z score for area 0.6500 = Z score for area 0.6517 = 0.39

Final answer :-

Z score for P₆₅ = 0.39