Question

Use the standard normal table to find the​ z-score that corresponds to the cumulative area 0.1190. If the area is not in the​ table, use the entry closest to the area. If the area is halfway between two​ entries, use the​ z-score halfway between the corresponding​ z-scores.

Answer 1

Let Z follow Normal(0,1)

The cumulative area for some z-score is given as 0.1190

Let z be that z-score

So, P(Z<=z)=0.1190

We found from the z-score table that for z= -1.18, the cumulative area is 0.1190 ,

i. e. P(Z<= -1.18)= 0.1190

So, the required z-score is (-1.18)

The z-score table is given below where 24 th row and 9th column (0.08) gives the above result :