Question

In: Biology

in a study of a population of field mice, you find that 49% of the mice...

in a study of a population of field mice, you find that 49% of the mice have a coat color that indicates that they are homozygous recessive. what would be the frequency of the dominant allele in this population?

Solutions

Expert Solution

Supposing the population size to be 100, according to the given information, the number of recessive individuals are 49 out of 100 (making it 49%). According to Hardy Weinberg law the allelic frequencies are constant if there are no evolutionary forces acting upon that population. The allelic frequencies are denoted by p (dominant allele) and q (recessive allele) and p+q=1. The genotypic frequencies are denoted by p2 (homozygous dominant), 2pq (heterozygous dominant) and q2 (homozygous recessive) and p2+2pq+q2 =1.

We have the percentage of homozygous recessive individuals i.e., 49% which means the frequency is 49/100 = 0.49

q2 = 0.49 hence, q= 0.7

Now since p+q=1, p=1-q

p=1-0.7

= 0.3

Since p represents the frequency of dominant allele, the answer would be 0.3.

To cross check our answer let's calculates 2pq

2pq= 2×0.7×0.3 = 0.42

Let's check if p2+2pq+q2 =1

p2 = 0.3×0.3 = 0.09

2pq = 2×0.3×0.7 = 0.42

q2 = 0.49

0.09+0.42+0.49=1

Hence, the answer 0.3 is right for frequency of dominant allele i.e., p.


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