In: Statistics and Probability
The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on average, the reduction in systolic blood pressure is 72.5 for a sample of size 27 and standard deviation 7.3. Estimate how much the drug will lower a typical patient's systolic blood pressure (using a 95% confidence level). Assume the data is from a normally distributed population.
Enter your answer as a tri-linear inequality accurate to three
decimal places.
< μμ <
Solution :
Given that,
= 72.5
s = 7.3
n = 27
Degrees of freedom = df = n - 1 = 27 - 1 = 26
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
t /2,df = t0.025,26 =2.060
Margin of error = E = t/2,df * (s /n)
= 2.060 * (7.3 / 27 )
= 2.888
Margin of error = 2.888
The 99% confidence interval estimate of the population mean is,
- E < < + E
72.5 - 2.888 < < 72.5 +2.888
69.612 < < 75.388
(69.612, 75.388 )