In: Statistics and Probability
The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on average, the reduction in systolic blood pressure is 40.9 for a sample of size 20 and standard deviation 11.7. Estimate how much the drug will lower a typical patient's systolic blood pressure (using a 98% confidence level). Assume the data is from a normally distributed population.
Enter your answer as a tri-linear inequality accurate to three decimal places
Answer:
Given that,
The effectiveness of a blood-pressure drug is being
investigated.
An experimenter finds that, on average, the reduction in systolic
blood pressure is 40.9 for a sample of size 20 and a standard
deviation of 11.7.
i.e,
=40.9
n=20 And,
=11.7
Estimate how much the drug will lower a typical patient's systolic blood pressure (using a 98% confidence level):
Given,
Assume the data is from a normally distributed population.
In order to obtain the lower patient's blood pressure. We first
obtain the confidence interval and the lower value of the
confidence interval indicates the patient's lower systolic blood
pressure.
For this let us consider, the null and alternative hypothesis as
follows:
Where
and
is the null and alternative hypothesis.
The confidence interval for the level of significance is given
as,
Where,
The level of significance
=1-98%=1-0.98=0.02
/2=0.01
The Z-critical value is obtained considering the normal distribution for a two-tailed confidence interval which is obtained for given level of significance.
i.e,
For a 98% confidence interval,
=(34.935, 46.865) (Approximately)
Therefore, the a 98% confidence interval is (34.935, 46.865).