In: Physics
Explain what physicists mean when they say that the de Broglie wavelength relates to the probability distribution wave function. Please be specific and do not copy and paste previous answers.
Consider a particle having momentum
. According to the wave-particle duality principle each and every
object can be described by a wavepocket with a de Broglie
wavelength
. The momentum and wavelength are related by
, where
is Planck's constant. Now suppose that in a quantum measurement a
particle has a uncertainty
in momentum
then what is the uncertainty in it's wavelength of the wavepocket
or what is the spread in the wavepocket representing the object?
Clearly it is
which is nothing but the Heisenberg uncertaintly principle, which
tells us that the product of the uncertainty in the momentum and
location of an object should be always greater than
. (Clearly, the concept of uncertainty means that the quantities
are given by some probability distribution). In this way the de
Broglie wavelength relates to the probability distribution wave
function or simply the wavepocket that represents the object which
we are talking about.