In: Advanced Math
The following are True or False statements. If True, give a simple justification. If False, justify, or better, give a counterexample.
1. (R,discrete) is a
complete metric space.
2. (Q,discrete) is a compact metric space.
3. Every continuous function from R to R maps an interval to an
interval.
4. The set {(x,y,z) : x2 −y3 + sin(xy) < 2} is open in R3
TRUE
.
Suppose
be a cauchy sequence in
.
In discrete space
for all
. Since
be a cauchy sequence so if we choose
then there exist
such that ,
for all
but since
for all
so ,
for all
.
That is the sequence
is an eventually constant sequence that is there
exist
such that for all
for all
.
The sequence
converges to
.
So every Cauchy sequence
in
is convergent .
Hence
is a complete metric space .
FALSE
.
In discrete metric space every every singleton set is open and so every subset in this metric space is open .
Consider the open cover of
given by ,
which do not have any finite subcover as union of any finite
subcollection will of the form
which donot cover whole
as
but
.
So this cover donot have any finite subcover .
Hence ,
is not compact metric space .
TRUE
.
Suppose
be a continuous map and
is an interval in
.
Now if image of the interval
is not open then there exist
such that
has no preimage under
for some
.
Now since
and
so by intermediate value property there exist
such that
.
So
has preimage under
, a contradiction to
has no preimage under
.
Hence image of
is also an interval .
TRUE
is defined by ,
which is a continuous map . As invese image of an open set is open
under continuous map and
is an open subset of
so
is open in
.
Now ,
so the set
is open in
.
.
.
.
If you have doubt at any step please comment and don't forget to rate the answer . Your rating keeps us motivated .