Question

Consider the following balanced equation: 2N2H4(g)+N2O4(g)→3N2(g)+4H2O(g) Complete the following table showing the appropriate number of moles of reactants and products. If the number of moles of a reactant is provided, fill in the required amount of the other reactant, as well as the moles of each product formed. If the number of moles of a product is provided, fill in the required amount of each reactant to make that amount of product, as well as the amount of the other product that is made.

Mol N2H4	Mol N2O4	Mol N2	Mol H2O
4	_____	_____	_____
_____	6	_____	_____
_____	_____	_____	10
4.5	_____	_____	_____
_____	4.5	_____	____
_____	_____	14.5	_____

Answer 1

We will be using the mole ratio to calculate the moles of required substance.

The given reaction is

2 N2H4 (g) + N2O4 (g) ---------------> 3 N2 (g) + 4 H2O (g)

Mol N2H4	Mol N2O4	Mol N2	Mol H2O
4	4 mol N2H4 * 1 mol N2O4/2 mol N2H4 = 2	4 mol N2H4 * 3 mol N2/ 2 mol N2H4 = 6	4 mol N2H4 * 4 mol H2O / 2 mol N2H4 = 8
6 mol N2O4 * 2 mol N2H4 /1 mol N2O4 = 12	6	6 mol N2O4 * 3 mol N2 /1 mol N2O4 = 18	6 mol N2O4 * 4 mol H2O /1 mol N2O4= 24
10 mol H2O * 2 mol N2H4/4 mol H2O = 5	10 mol H2O * 1 mol N2O4/4 mol H2O = 2.5	10 mol H2O * 3 mol N2/4 mol H2O = 7.5	10
4.5	4.5 mol N2H4 * 1 mol N2O4/2 mol N2H4 = 2.25	4.5 mol N2H4 * 3 mol N2/ 2 mol N2H4 = 6.75	4.5 mol N2H4 * 4 mol H2O / 2 mol N2H4 = 9
4.5 mol N2O4 * 2 mol N2H4 /1 mol N2O4 = 9.0	4.5	4.5 mol N2O4 * 3 mol N2 /1 mol N2O4 = 13.5	4.5 mol N2O4 * 4 mol H2O /1 mol N2O4= 18
14.5 mol N2 * 2 mol N2H4/3 mol N2 = 9.67	14.5 mol N2 * 1 mol N2O4/3 mol N2 = 4.83	14.5	14.5 mol N2 * 4 mol H2O/3 mol N2 = 19.3