In: Chemistry
Use Charles's law to complete the following table (assume pressure and number of moles of gas to be constant):
| V1 | T1 | V2 | T2 |
| 117L | 11.3?C | -- | 120.4?C |
| -- | 129K | 174L | 308K |
| 2.13L | 14.4?C | 2.43L | -- |
| 15.9cm3 | -- | 19.9cm3 | 11.4?C |
Charles's law states that the volume of a fixed amount of gas at constant pressure is directly proportional to temperature of the gas .
V
T
For two cases
Where
V1 = initial volume
V2 = final volume
T1 = initial temperature
T2 = final temperature
(1) Given
V1 = initial volume = 117 L
V2 = final volume = ?
T1 = initial temperature = 11.3 oC = 11.3 + 273 = 284.3K
T2 = final temperature = 120.4 oC = 120.4 + 273 = 393.4 K
So
(2) Given
V1 = initial volume = ?
V2 = final volume = 174 L
T1 = initial temperature = 129 K
T2 = final temperature = 308 K
So
(3)Given
V1 = initial volume = 2.13 L
V2 = final volume = 2.43 L
T1 = initial temperature = 14.4 oC = 14.4 + 273 = 287.4 K
T2 = final temperature = ?
So
(4)Given
V1 = initial volume = 15.9 cm3
V2 = final volume = 19.9 cm 3
T1 = initial temperature = ?
T2 = final temperature = 11.4 oC = 11.4 + 273 = 284.4 K
So
Therefore the table becomes
| V1 | T1 | V2 | T2 |
| 117L | 11.3?C | 161.9L | 120.4?C |
| 72.9L | 129K | 174L | 308K |
| 2.13L | 14.4?C | 2.43L | 327.9oC |
| 15.9cm3 | -45.8oC | 19.9cm3 | 11.4?C |