In: Statistics and Probability
2. The following data refers to airborne bacteria count (number
of colonies/ft3) both for m = 8
carpeted (1) hospital rooms and for n = 8 uncarpeted (2) rooms.
Make any necessary
assumptions and answer the questions below.
Carpeted 11.8, 8.2, 7.1, 13.0, 10.8, 10.1, 14.6, 14.0
Uncarpeted 12.1, 8.3, 3.8, 7.2, 12.0, 11.1, 10.1, 13.7
a. Is the evidence sufficient to support the variance for carpeted
rooms being greater than 8
(colonies/ft3)2 at level 0.1?
b. Give a 95% confidence interval for the standard deviation of
carpeted rooms.
c. Is the evidence sufficient to support the variance for
uncarpeted rooms being greater than
10 (colonies/ft3)2 at level 0.1?
d. What is the P-value for the test in part “c.”?
e. Is the evidence sufficient to support the variance for
uncarpeted rooms being greater than
the variance for carpeted rooms at level 0.1?
f. What is the P-value for the test in part “a.”?
g. Give a 97% confidence interval for the variance of bacteria
count in carpeted rooms over
the variance of bacteria count in uncarpeted rooms.
a)
Following table shows the calculations for variance of carpeted room :
X | (X-mean)^2 | |
11.8 | 0.36 | |
8.2 | 9 | |
7.1 | 16.81 | |
13 | 3.24 | |
10.8 | 0.16 | |
10.1 | 1.21 | |
14.6 | 11.56 | |
14 | 7.84 | |
Total | 89.6 | 50.18 |
Conclusion : The evidence is not sufficient to support the
variance for carpeted rooms being greater than 8
(colonies/ft3)2 at level 0.1.
(b)
(c)
Following table shows the calculations for variance of uncarpeted room:
X | (X-mean)^2 | |
12.1 | 5.3361 | |
8.3 | 2.2201 | |
3.8 | 35.8801 | |
7.2 | 6.7081 | |
12 | 4.8841 | |
11.1 | 1.7161 | |
10.1 | 0.0961 | |
13.7 | 15.2881 | |
Total | 78.3 | 72.1288 |
Conclusion; The evidence is not sufficient to support the
variance for uncarpeted rooms being greater than
10 (colonies/ft3)2 at level 0.1.
(d)
The p-value is 0.4073