In: Accounting
Caro Manufacturing has two production departments, Machining and Assembly, and two service departments, Maintenance and Cafeteria. Direct costs for each department and the proportion of service costs used by the various departments for the month of August follow:
Proportion of Services Used by | |||||||||||
Department | Direct Costs | Maintenance | Cafeteria | Machining | Assembly | ||||||
Machining | $ | 120,000 | |||||||||
Assembly | 84,000 | ||||||||||
Maintenance | 55,000 | — | 0.2 | 0.5 | 0.3 | ||||||
Cafeteria | 42,000 | 0.7 | — | 0.2 | 0.1 | ||||||
Required:
Use the reciprocal method to allocate the service costs. (Matrix algebra is not required.) (Negative amounts should be indicated by a minus sign. Do not round intermediate calculations. Round your final answers to the nearest whole dollar amounts.)
Maintenance | Personnel | Printing | Developing | |
Service department costs | ||||
Maintenance | ||||
Personnel | ||||
Total | $0 | $0 | $0 | $0 |
Reciprocal method |
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The separate expense maintenance is 55,000. But it gets the allocation from cafeteria expense to the extent of 70%. Suppose the total expense of maintenance is X and total expense of the cafeteria is Y. hence, the total expense of X will be |
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X's total expense = 55,000 + 70/100(Y) |
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X = 55,000 + 0.7 (Y) ........... (1) |
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similarly, the separate expense of Y is 42,000 but to this will be added 20% of the expense of X, hence, total expense of Y will be |
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Y's total expense = 42,000 + 20/100 (X) |
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Y = 42,000 + 0.2(X) ........(2) |
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if we put value of X = X = 55,000 + 0.7 (Y) in this equation we get |
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Y = 42,000 + 0.2 (55,000 + 0.7 (Y)) |
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Y = 42,000 +11,000 + 0.14Y |
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0.86Y = 53,000 |
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Y = 61,628, hence cafeteria expense (including maintenance) = 61,628…put in equation 1 X = 55,000 +0.7 (61,628) X = 55,000 + 43,140 X = 98,140, hence maintenance expense (including maintenance cafeteria) = 61,628
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