Question

In: Chemistry

The table of diprotic acids below shows how the acidity of the 1st proton is always...

The table of diprotic acids below shows how the acidity of the 1st proton is always much higher than the acidity of the second proton.Thus, the pH of the solution is dominated by the equilibrium for the loss of the 1st proton.

Compound	K_a1	K_a2
H₂CO₃	4.3 X 10^-7	5.6 X10^-11
H₂S	8.9 X 10^-8	1.0 X 10^-19
H₂Te	2.3 X 10^-3	1.6 X 10^-11
H₂SO₃	1.7 X 10^-2	6.4 X 10^-8

What is the pH for a 1.12 M solution of Li2S?

Expert Solution

Concentration of Li2S = 1.12M

Li2S ------------------ 2 Li+ + S-2

S-2 + H2O ---------------- HS- + OH-

1.12 0 0

-x +x +x

1.12-x +x +x

Ka = 8.9x10^-8

Ka x Kb = Kw where Kw = 1.0x10^-14

Kb = Kw/Ka = 1.0x10^-14/8.9x10^-8 = 1.12 x10^-7

Kb= 1.12x10^-7

Kb = [HS-][OH-]/[S-2]

1.12x10^-7 = x*x/(1.12-x)

for solving the equation

x= 0.000354

[OH-] = 0.000354M

-log[OH-] = -log(0.000354)

POH= 3.45

PH+POH= 14

PH = 14-POH

PH= 14-3.45

PH= 10.55.

queen_honey_blossom answered 1 year ago

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