In: Biology
Glucose are stored as glycogen in muscle cells, from which it
can again be mobilized during exercise.
a) Write down the partial reactions as well as the net yield for
the conversion of glucose-6-phosphate to glycogen and for the
conversion of glycogen to glucose-6-phosphate.
b) Calculate the energy required for the consumption of the total
process of converting glucose-6-phosphate to glycogen and back to
glucose-6-phosphate expressed as energy-rich phosphate bonds (ATP
equivalents).
ΔG0’ for the reaction: ATP + H2O → ADP + Pi = –30.5 kJ∙mol-1.
c) Calculate ΔG’ for the reaction at 25 °C and pH 7, when [ATP] = 5
mM, [ADP] = 0.5 mM and [Pi] = 1.0 mM.
Phosphocreatin constitutes a small extra storage of energy within
muscle cells, and is formed from phosphorylation of creatin. The
reaction is catalyzed by creatine kinase and ΔG0’ for the reaction
is +2.3 kJ∙mol-1 (progressing towared the formation of
phosphocreatin).
d) Calculate how much phosphocreatin formed relative to creatin at
equilibrium in the creatin kinase catalyzed reaction (assuming the
same temperature, pH and concentrations of ATP and ADP as indicated
in the previous question).
Answer:
a):
glucose-6-phosphate to glycogen:
Glycogen to glucose-6-phosphate:
b):
c) :
= -30.5 - (0.0083*298*ln 0.5*1/5)
= -30.5 +5.695 = -24.805 kJ/mol/K
d):
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